added array-minimum-distance

master
Furkan Türkal 7 years ago
parent 999ef88bcc
commit 6d3c3b28a7

@ -1,2 +1 @@
# Data-Structures-with-Go
Data Structures with Go Language
<h1 align="center">Data Structures wih Go Language Public Source Repository</h1>

@ -0,0 +1,33 @@
<h1 align="center">Array Minimum Distance Source</h1>
[What It Is](#what-it-is)
## What It Is
* Given an unsorted array `arr[]` and two numbers x and y, find the minimum distance between `x` and `y` in `arr[]`. The array might also contain duplicates. You may assume that both `x` and `y` are different and present in `arr[]`.
Examples
--------------------------
> Input: arr[] = {1, 2}, x = 1, y = 2
> Output: Minimum distance between 1 and 2 is 1.
> Input: arr[] = {3, 4, 5}, x = 3, y = 5
> Output: Minimum distance between 3 and 5 is 2.
> Input: arr[] = {3, 5, 4, 2, 6, 5, 6, 6, 5, 4, 8, 3}, x = 3, y = 6
> Output: Minimum distance between 3 and 6 is 4.
> Input: arr[] = {2, 5, 3, 5, 4, 4, 2, 3}, x = 3, y = 2
> Output: Minimum distance between 3 and 2 is 1.
**METHOD 1 (Simple)**
Use two loops: The outer loop picks all the elements of arr[] one by one. The inner loop picks all the elements after the element picked by outer loop. If the elements picked by outer and inner loops have same values as x or y then if needed update the minimum distance calculated so far.
Algorithm Complexity
--------------------------
| Complexity | Notation |
| ----------------- |:---------:|
| `Time Complexity` | `O(n^2)` |

@ -0,0 +1,49 @@
// ====================================================
// Data-Structures-with-Go Copyright(C) 2017 Furkan Türkal
// This program comes with ABSOLUTELY NO WARRANTY; This is free software,
// and you are welcome to redistribute it under certain conditions; See
// file LICENSE, which is part of this source code package, for details.
// ====================================================
package main
import "fmt"
const MaxUint = ^uint(0)
const MinUint = 0
const MaxInt = int(MaxUint >> 1)
const MinInt = -MaxInt - 1
func Abs(x int) int {
if x < 0 {
return -x
}
if x == 0 {
return 0
}
return x
}
func minDist (arr []int, n, x, y int) int {
var min_dist int = MaxInt
for i := 0; i < n; i++ {
for j := i + 1; j < n; j++ {
if ((x == arr[i] && y == arr[j] || y == arr[i] && x == arr[j]) && min_dist > Abs(i - j)) {
min_dist = Abs(i - j)
}
}
}
return min_dist
}
func main() {
arr := []int{3, 5, 4, 2, 6, 5, 6, 6, 5, 4, 8, 3}
var n int = len(arr)
var x int = 3
var y int = 6
fmt.Printf("Minimum distance between %d and %d is %d", x, y, minDist(arr, n, x, y))
}

@ -2,8 +2,6 @@
[What It Is](#what-it-is)
[How To Use](#how-to-use)
## What It Is
* Write a function `rotate(ar[], d, n)` that rotates `arr[]` of size `n` by `d` elements
@ -55,8 +53,4 @@ Algorithm Complexity
| Complexity | Notation |
| ----------------- |:---------:|
| `Time Complexity` | `O(n*d)` |
| `Auxiliary Space` | `O(1)` |
## How To Use
| `Auxiliary Space` | `O(1)` |
Loading…
Cancel
Save